Question

3 coins are tossed simultaneously find probability of getting (1)at least two head (2)atmost two head (3) new tail (4)exactly two head​

Answer 1

Total no. Of chances =150

(1).No. of chances having two head= 80

P(at least two head)= no.of favorable event/ total no. of event

80/150=8/15

(2) No. Of chances having at most two heads =20 + 80 = 100

Required probability =100/150= 2/3

Answer 2

Step-by-step explanation:

for answer please see picture