Question

3. Combine terms: 12a + 26b -4b – 16a.

(a) 4a + 22b,

(b) -28a + 30b,

(c) -4a + 22b,

(d) 28a + 30b.
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Answer 1

$\mathfrak{\underline{\underline{Question :}}}$

3. Combine terms: 12a + 26b -4b – 16a.

(a) 4a + 22b,

(b) -28a + 30b,

(c) -4a + 22b,

(d) 28a + 30b.

$\bold{Answer :-}$

12a + 26b -4b – 16a.

Rearranging the terms

= 12a – 16a + 26b – 4b.

Subtracting 16 from 12 gives negative 4 as 16 is a bigger number

Subtracting 4 from 26 gives positive 22 as 26 is bigger number

= -4a + 22b.

We can't solve it, hereafter.

So, that's our final answer

Answer: (c)

Answer 2

12a + 26b -4b – 16a.

Rearranging the terms

= 12a – 16a + 26b – 4b.

Subtracting 16 from 12 gives negative 4 as 16 is a bigger number

Subtracting 4 from 26 gives positive 22 as 26 is bigger number

= -4a + 22b.

We can't solve it, hereafter.

So, that's our final answer

Answer: (c)