3) Complete the activity to find the value of
3 + 2 = 11 −---- (I)
and 2 + 3 = 4 ------(II)
Solution:
Multiply equation (I) by ----- and equation (II) by -----
-----. × (3 + 2 = 11) ∴ 9 + 6 = 33 2
----- × (2 + 3 = 4) ∴ 4 + 6 = 8 subtract (II) from (I), ----- = 25
∴ = ----
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Answer:
Noo this is wrong
First we adding eq 1 and 2
3x+2y=11
2x+3y=4
5x+5y=15
Dividing by 5 from all sides
5 upon 5+5 upon 5=15 upon 5
X+y=3______3
Subtracting eq1 or 2
3x +2y = 11
2x +3y = 4
x-y=7.______4
Adding eq4 and 3
x-y=7
x+y=3
2 y=4
Y=4 upon 2
Y=2
Putting the value of y=2 in eq 3rd
X+y=3
X+2=3
X=3-2
X=1
Step-by-step explanation:
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