Physics, asked by nidafatima001o, 8 months ago

-
3 concentric thin conducting
Shells bave radii in ratio of
1 :2 :3 .What is the ratio of
changes given to them if the
surface charge density on the
outer surfaces of the shells is
same ?​

Answers

Answered by subualaxminayak696
6

Answer:

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Answered by sumitsilodiya214
2

Answer:

ANSWER

In metallic shell , all charge will appear on the outer surface of outer shell and charge inside each is zero.

The charge distributions among the shells will occur in such a way that the charge inside each shell is zero and total charge will appear on the outer surface of outer shell. (shown in fig below)

Let surface density of charges of outer surfaces of each shell is σ.

now, Q1=σ.4πR2,

Q1+Q2=σ.4π(2R)2⇒Q2=σ.4π4R2−Q1=σ.4π4R2−σ.4πR2

=3(σ.4πR2)

and

Q1+Q2+Q3=σ.4π(3R)2

⇒Q3=σ.4π9R2−(Q1+Q2)=σ.4π9R2−σ.4π4R2=5(σ.4πR2)

thus, Q1:Q2:Q3=1:3:5

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