3 consecutive even numbers are such that the largest of them is twice the smallest. Find the second largest number among the three
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let the 1st no be s
•°• other nos are s+1 , s+2
ATP,
=> s+2= 2s
=> 2s-s=2
=> s=2
now logically , s+1 < s+2 > s
•°• highest no = s+2 = 2+2 =4
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