Question

3 consecutive positive even integers whose sum is 216

Answer 1

Step-by-step explanation:

Let the integers be x, x+2,x+4

x+x+2+x+4=216

3x=216-6

3x=210

x=210/3

x=70

x+2=72

x+4=74

70,72,74 are three consecutive even integers whose sum is 216

Hope it helps ✌✌

Answer 2

Answer:

Let the first integer be x

Therefore, the other two integers are x+2 and x+4, respectively.

Now, according to the question,

x+x+2+x+4=216

3x+6=216

3x=216-6

=210

x=210/3

=70

x+2=70+2

=72

x+4=70+4

=74