3 consecutive positive integers are such that the sum of the the square of the first no. and the product of the other two numbers is 46. Find the integers.
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let the integers be x, x+1,x+2
x^2+(x+1)(x+2)=46
x^2+x^2+3x+2=46
2x^2+3x-44=0
Find the roots of the equation by quadratic formula
a= 2 ,b= 3 ,c= -44
b^2-4ac= 9 + 352
b^2-4ac= 361



x1=( -3 + 19 )/ 4
x1= 4
x2=( -3 -19 ) / 4
x2= -5.5
They are integers 4,5,6
x^2+(x+1)(x+2)=46
x^2+x^2+3x+2=46
2x^2+3x-44=0
Find the roots of the equation by quadratic formula
a= 2 ,b= 3 ,c= -44
b^2-4ac= 9 + 352
b^2-4ac= 361



x1=( -3 + 19 )/ 4
x1= 4
x2=( -3 -19 ) / 4
x2= -5.5
They are integers 4,5,6
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