3. Construct 11 DEF suchthat DE= 5cm, DF = 3cm and m L. EDF =90°.
Answers
Answered by
0
Answer:
☺︎︎☺︎︎☺︎︎ꨄ︎☻︎☻︎☻︎✔︎☹︎☹︎☹︎ఌ︎☺︎︎☺︎︎☺︎︎☏︎☻︎☺︎︎
Step-by-step explanation:
☀︎︎☏︎✞︎✔︎✔︎✔︎☀︎︎☏︎☹︎❥︎❥︎❥︎♫︎ఌ︎ت︎
Answered by
1
Answer:
\Delta DEF such that DE = 5 cm, DF = 3 cm and m\angle EDF=90^{\circ}:
1. Draw a line DE = 5cm
2. Draw a line DX making 90 degrees with DE.
3. cut the length DF =3cm using the compass on the line DX
4. Join E and F
DEF is the required triangle
Similar questions