Question

3. Construct 11 DEF suchthat DE= 5cm, DF = 3cm and m L. EDF =90°.

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

\Delta DEF such that DE = 5 cm, DF = 3 cm and m\angle EDF=90^{\circ}:

1. Draw a line DE = 5cm

2. Draw a line DX making 90 degrees with DE.

3. cut the length DF =3cm using the compass on the line DX

4. Join E and F

DEF is the required triangle