Question

3. Construct a quadrilateral ABCD with AB = 5.5 cm, AD = 6 cm, ZA = 120", ZD = 90' and 2B = 40" m, QR = 5 cm, P = 60° and 20 = 120​

Answer 1

Answer:

⇒ Draw a line segment AB = 5cm.

⇒ With A as a center and radius AC = 5cm, draw an arc.

⇒ With B as a center and radius BC = 6cm, draw an arc, intersecting the previous arc at point C.

⇒ With A as a center and radius AD = 3cm, draw an arc.

⇒ Take C as a center with radius CD = 4cm draw an arc intersecting the previous arc at point D.

⇒ Join AC, BC, AD and CD.

Thus, ABCD is a required quadrilateral

Answer 2

Answer:

Steps of Construction:

(i) Construct BC = 6 cm.

(ii) At the point B, draw ∠CBP = 45

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(iii) At the point C, draw ∠BCQ = 90

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(iv) Cut off CD = 4 cm from CQ.

(v) At the point D, draw ∠CDR = 120

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(iv) Let BP and DR meet at the point A.

Therefore, ABCD is the required quadrilateral.

solution