Question

3
Construct a quadrilateral EFGH, in which
EF = 6.1 cm, FG = 4.5 cm, GH = 5 cm,
HE = 5.2 cm and FH = 7.3 cm.

Answer 1

Step-by-step explanation:

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ANSWER

Given: In the Cyclic Quadrilateral EFGH

EF=5.2cm, ∠GEF=50° , FG=6cm and ∠EGH=40°

.

Construction:

(i) Draw a rough diagram and mark the measurements. Draw a line segment EF=5.2cm.

(ii) From E, draw EX such that ∠FEX=50°.

(iii) With F as centre and radius 6cm, draw an arc intersecting EX at G.

(iv) Join FG.

(v) Draw the perpendicular bisectors of EF and FG intersecting each other at O.

(vi) With O as centre and OE(=OF=OG) as radius, draw a circumcircle.

(vii) From G, draw GY such that ∠EGY=40°.

which interscets the circle at H.

(viii) Join EH.

Now, EFGH is the required cyclic quadrilateral.

Answer 2

Step-by-step explanation:

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