Question

3. Construct a quadrilaterals PQRS in which
(a) PQ = 2cm, QR = 3.6cm, PS = 3.2 cm,
ZP = 90° and ZQ = 120°
(b) PQ = QR = RS = 5cm and
ZQ = ZR = 90° . ​

Answer 1

Steps of Construction:

(i) Construct a line segment PR = 6.5 cm.

(ii) Taking P as centre and 4.5 cm radius and R as centre and 6 cm radius construct arcs which intersect each other at Q.

(iii) Now join PQ and QR.

(iv) Taking P as centre and 5 cm radius and R as centre and 5.5 cm radius, construct arcs which intersect each other at S.

(v) Join PS and SR.

Hence, PQRS is the required quadrilateral.

Answer 2

Answer:

Steps of Construction:

(i) Construct a line segment QR = 5 cm.

(ii) At the point Q, construct a ray QX making an angle of 60

⋅

and cut off QP = 4 cm.

(iii) At the point R, construct a ray RY making an angle of 90

⋅

and cut off RS = 4.5 cm.

(iv) Now join PS.

Therefore, PQRS is the required quadrilateral.

Step-by-step explanation:

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