3.Copper metal rects with conctrated HNO, as
Cu + 4HNO, 4 Cu(NO3)2 + 2NO, + 2H,0 .
The number of moles of the HNO, reduced
by one mole of the Cu will be
1) 4 2) 2 3) 0.5 4) 0.25
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Answer:
answer is option 2 for your question
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