Question

√3(cos π/6+isin π/6)​

Answer 1

Answer:

√3(cos 180/6+isin 180/6)

[π=180 ]

√3(cos 30°+isin 30°)

√3(√3/2+ 1/2i)

3/2+√3/2i

1.5+0.8815i which is in the form of a+ib complex number form, where a=1.5 and b=0.8815

Answer 2

Step-by-step explanation:

√3(cos π/6+sin π/6)

divide by 2

√3/2 (cos π/6 ×1/2+sin π/6×1/2)

√3/2 (cos π/6 cos theta°+ sin π/6 sin theta°)

√3/2 cos(π/6 - theta)

√3/2 cos [30-(60+30)]

√3/2 cos [-60°]

√3/2 - 1/2

$\frac{ \sqrt{3 - 1} }{2}$