Math, asked by sahensingh69, 6 months ago

3 cos 80° cosec 10° + 2 sin 59° sec 31º.​

Answers

Answered by virajchauhan7070
1

Answer:

=3cos80×1/sin10+2sin59×1/cos31

=3cos80+1/cos31=2sin59×1/sin10

=1/2

Answered by aktshayaa7a20192020
0

Answer:

5

Step-by-step explanation:

3 cos (90 - 10) x cosec 10 + 2 sin 59 x sec (90 - 59)     [cos (90 - A) = sin A]

3 sin 10 x cosec 10 + 2 sin 59 x cosec 59                              (sin x cosec = 1)

3 + 2 = 5

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