3 cos A = 2 sin2 A find A=?
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Answered by
4
3cosA = 2sin2A
3cosA=2 * 2sinAcosA........... since (2sinA=2sinAcosA)
3cosA=4sinAcosA
3=4sinA
sinA = 3/4
A =sin^-1(3/4)
3cosA=2 * 2sinAcosA........... since (2sinA=2sinAcosA)
3cosA=4sinAcosA
3=4sinA
sinA = 3/4
A =sin^-1(3/4)
Answered by
1
Given: 3cosA=2sin2A
3cosA=4sinAcosA
3=4sinA
sinA=3/4
A=sin^-1(3/4)
3cosA=4sinAcosA
3=4sinA
sinA=3/4
A=sin^-1(3/4)
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