Question

3 cos a = 4 sin a find value of 4 cos^2a - 3 sin^2 a +2

Answer 1

Answer:

8725

Step-by-step explanation:

Given  

4sina=3cosa

⇒tana=34

Now  

4cos2a−3sin2a+2

=4cos2a−3sin2a+2cos2a+sin2a

=4cos2acos2a−3sin2acos2a+2cos2acos2acos2a+sin2acos2a

=4−3tan2a+2sec2a1+tan2a

=4−3tan2a+2+2tanaθ1+tan2a

=6−tan2a1+tan2a

=6−(34)21+(34)2

=6⋅16−916+9

=8725

Answer 2

Answer:87/25

Step-by-step explanation: