Question

3 cos theta=2 sin theta then the value of cot^2 theta is?

Answer 1

Answer:

$3 \: cos \theta \: = 2 \: sin \theta \\ dividing \: both \: sides \: by \: 3 \: sin \theta: \\ \frac{3 \: cos \theta}{3 \: sin \theta} = \frac{2 \: sin \theta}{3 \: sin \theta} \\ cot \theta \: = \frac{2}{3} \\ {cot}^{2} \theta = {( \frac{2}{3} })^{2} \\ \implies \: {cot}^{2} \theta = \frac{4}{9}$