Math, asked by kabir40012, 11 months ago

√3 cos theta + sin theta = 1
solve the equation.​

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Answers

Answered by spiderman2019
19

Answer:

θ = 2nπ-π/6 or 2nπ+π/2

Step-by-step explanation:

√3 cosθ + Sinθ = 1

//divide by 2 on both sides.

√3/2 Cosθ + 1/2Sinθ = 1/2

Sinπ/3*Cosθ + CosΠ/3*Sinθ = Sinπ/6

//L.H.S is of form Sin(A+B) = SinACosB+ CosASinB

Sin(π/3 + θ) = Sinπ/6

π/3 + θ = 2nπ+π/6 or 2nπ + 5π/6

θ = 2nπ-π/6 or 2nπ+π/2

Answered by soumilishr143
11

Answer:

Hope it helps you..

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