√3 cos theta + sin theta = 1
solve the equation.
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19
Answer:
θ = 2nπ-π/6 or 2nπ+π/2
Step-by-step explanation:
√3 cosθ + Sinθ = 1
//divide by 2 on both sides.
√3/2 Cosθ + 1/2Sinθ = 1/2
Sinπ/3*Cosθ + CosΠ/3*Sinθ = Sinπ/6
//L.H.S is of form Sin(A+B) = SinACosB+ CosASinB
Sin(π/3 + θ) = Sinπ/6
π/3 + θ = 2nπ+π/6 or 2nπ + 5π/6
θ = 2nπ-π/6 or 2nπ+π/2
Answered by
11
Answer:
Hope it helps you..
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