Math, asked by kunkav, 9 hours ago

3+CosA/ 1-cosA =1/2(Cot^2A-tan^2A. Is it correct.

Answers

Answered by nishii1009

1

Answer:

LHS :

1+sinA

cosA

+

cosA

1+sinA

=

(1+sinA)(cosA)

cos

2

A+(1+sinA)

2

=

(1+sinA)(cosA)

1+sin

2

A+cos

2

A+2sinA

=

(1+sinA)(cosA)

2+2sinA

=

(1+sinA)(cosA)

2(1+sinA)

=

cosA

2

=2secA

=RHS

Answered by makadiyamausmee123

0

Answer:

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