Question

3 cosec square (80degree-2x) = 4 then find x​

Answer 1

Answer:

Step-by-step explanation:

Given  

3 cosec square (80degree-2x) = 4 then find x

3 cosec^2 (80 – 2x) = 4

Cosec^2 (80 – 2x) = 4/3

We get positive and negative values.

So cosec (80 – 2x) = 2 / √3

Now 1/sin (80 – 2x) = 2 / √3

Or sin (80 – 2x) = √3 / 2

We know that sin 60 = √3/2

Sin (80 – 2x) = sin 60

So 80 – 2x = 60

Or – 2x = - 20

So x = 10

Now considering negative value we get

Cosec (80 – 2x) = - 2 / √3

Sin (80 – 2x) = - √3 / 2

So sin (80 – 2x) = sin (- 60)

80 – 2 x = - 60

 So – 2x = - 140

So x = 70