Question

3 cot 40/tan 50-1/2(cos 35/sin 55)
Pls solve it at the earliest it is very very urgent!!!!

Answer 1

Answer::

3 cot 40/ tan50 -1/2x cos 35/sin55

= 3-1/2=5/2

Answer 2

The required value is 2.

Step-by-step explanation:

Since we have given that

$\dfrac{3\cot 40}{\tan 50^\circ}-\dfrac{1}{2}\dfrac{\cos 35^\circ}{\sin 55^\circ}\\\\=3\dfrac{\tan (90-50)}{\tan 50^\circ}-\dfrac{\cos 35^\circ}{\cos (90-35)}\\\\=3\dfrac{\tan 50}{\tan 50}-\dfrac{\cos 35}{\cos 35}\\\\=3-1\\\\=2$

Hence, the required value is 2.

# learn more:

3 cot 40/tan 50-1/2(cos 35/sin 55)

Pls solve it at the earliest it is very very urgent!!!!

https://brainly.in/question/15929489