Question

3 cot A is equals to 4 find the value of cos square A minus sin square A ​

Answer 1

Therefore cosA=$\dfrac{4}{5}$

Answer:

$cos^{2}A-sin^{2}A=\dfrac{7}{25}$

Step-by-step explanation:

We have given that 3cotA=4, i.e. $cotA=\dfrac{4}{3}$

=$\dfrac{B}{P}$

Therefore $H=\sqrt{B^{2}+P^{2}  }$

$H=\sqrt{9+16} =5$

$cos^{2}A=\dfrac{16}{25}$

sinA=$\dfrac{3}{5}$

$sin^{2}A=\dfrac{9}{25}$

Therefore the final answer would be

$cos^{2}A-sin^{2}A=\dfrac{16}{25}-\dfrac{9}{25}$=$\dfrac{7}{25}$

Answer 2

Step-by-step explanation:

i hope this answer helps you