3 cot theta =4 then find the value of cos square theta minus sin square theta
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Solution :-
3 cot θ = 4
⇒ cot θ = 4/3
On taking its reciprocal
⇒ tan θ = 3/4
⇒ Opposite side ÷ Adjacent side = 3/4
This is a simple case of right angled triangle in which the sides are 3 cm and 4 cm and Hypotenuse is 5 cm.
So, sin θ = Opposite side ÷ Hypotenuse
→ sin θ = 3 ÷ 5
→ sin θ = 3/5
cos θ = Adjacent side ÷ Hypotenuse
→ cos θ = 4 ÷ 5
→ cos θ = 4/5
For finding the value of cos²θ - sin²θ
→ cos²θ - sin²θ = (4/5)² - (3/5)²
→ cos²θ - sin²θ = 16/25 - 9/25
→ cos²θ - sin²θ = 7/25
∴ cos²θ - sin²θ = ⁷/₂₅
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