Question

3 cot40/tan 50-1/2(cos35/sin55)

Answer 1

$\bf\large\underline\purple{Solution:-}$

Cot (90-50)/tan 50 -1/2 cos(90-55)/sin55

tan 50/tan50 - 1/2 sin55/sin55

1 - 1/2*1 =1/2

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Answer 2

$\huge\star\mathfrak\blue{{Answer:-}}$

Cot (90-50)/tan 50 -1/2 cos(90-55)/sin55

tan 50/tan50 - 1/2 sin55/sin55

1 - 1/2*1 =1/2