Question

3 cotA = 2 then find 2 sinA - 3 cosA/ 2 sinA + 3 cos A answer it fast plzz #nospam ​

Answer 1

Step-by-step explanation:

Solution :

Given 3cotA = 2

=> cotA = 2/3 ----( 1 )

Now ,

( 2sinA - cosA )/( 2sinA + 3cosA )

Divide Numerator and denominator

by sinA , we get

= ( 2 - cotA )/( 2 + 3cotA )

= [ 2 - ( 2/3 )]/[ 2 + 3( 2/3 ) ]

= [ 6 - 2 ]/( 6 + 6 )

= 4/12

= 1/3

ਸਵੇਰੇ ਜਲਦੀ aw jea ਕਰੋ , ਜਦੋਂ ਆਉਗੇ ਮੇਰੇ qus ਤੇ ਅਵ ਜਿਓਂ।।

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hope it helps you

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