Question

3 cotA= 4 investigate that 1- tansquareA/1+ tansquareA​

Answer 1

See the above attachment...

Answer 2

$\huge{\underline{\tt{SOLUTION:-}}}$

→ 3 cot A = 4

then cot A = 4/3

we know that cot A = 1/tanA

→ tan A = 3/4

putting tanA = 3/4 into

$\longrightarrow \tt{\frac{1 - tan {}^{2}A }{1 + tan {}^{2} A} }$

$\longrightarrow \: \tt\frac{1 - ({ \frac{3}{4}) }^{2} }{1 +( { \frac{3}{4} )}^{2} }$

$\longrightarrow \tt{ \frac{1 - \frac{9}{16} }{1 + \frac{9}{16} }}$

$\longrightarrow \tt{ \frac{ \frac{7}{ \cancel{16}} }{ \frac{ 25}{ \cancel{16} }} }$

$\longrightarrow \: \boxed{ \bf \frac{7}{25} }$