3
cubes
Each of volume 64 cm² are joinedend to end the surface area of the rustling cubiod is
احد
Cabiod is
و سریع علو
Answers
Answered by
2
Answer:
volume of cube = 64cm^3
(l)^3 = 64cm^3
l = 4cm
now, after joining the 3 cubes
length = 4cm
height = 4cm
breathe = 4cm+4cm+4cm
= 12cm
hence,
volume of cuboid= l×b×h
= 4cm×12cm×4cm
= 192cm^3 ans.
surface area of cuboid= 2(lb+bh+hl)
=2(4×12+12×4+4×4)cm^2
=2(48+48+16)cm^2
=2(72)cm^2
= 144cm^2 ans.
Similar questions