3 cubes of a metal whose edges 3 cm, 4 cm and 5 cm are melted to form a single cube. Find the total surface area of the cube so formed.
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volume of 1st cube = 3x3x3
= 27cm^3
volume of 2nd cube = 4x4x4
= 64cm^3
volume of 3rd cube = 5x5x5
= 125cm^3
volume of new cube formed = 125+64+27
= 216cm^3
side of cube = a
axaxa=216
a=6cm
surface area = 6 a^2
= 6x6x6
= 216cm^2
= 27cm^3
volume of 2nd cube = 4x4x4
= 64cm^3
volume of 3rd cube = 5x5x5
= 125cm^3
volume of new cube formed = 125+64+27
= 216cm^3
side of cube = a
axaxa=216
a=6cm
surface area = 6 a^2
= 6x6x6
= 216cm^2
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Answered by
0
Volume of 3 cubes=3^3+4^3+5^3=216
Volume of new cube=216
Edge of the new cube =cube root of 216=6
Total surface area =6*6=36sq cm
Volume of new cube=216
Edge of the new cube =cube root of 216=6
Total surface area =6*6=36sq cm
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