3 cubes of
volume 27cm^3 are
joined
to end.
find
the
S.A
the
resulting cuboid.
Answers
90 cm²
Explanation:
Given:
3 Cubes of volume 27 cm³ are joined end to end.
To find:
Total Surface Area (T.S.A)
Solution:
Volume of cube = 27 cm³
So the side of each cube is 3 cm.
All the cubes are joined end to end. (See In Attachment)
Length(l) of new cuboid = (3+3+3)
= 9 cm
Breadth(b) = 3 cm
Height(h) = 3 cm
So, T.S.A = 2(lb+bh+lh)
= 2{(9×3)+(3×3)+(3×3)}
= 2(27 + 9 + 9) cm²
= 2(45) cm²
= 90 cm²
Additional Information:
Cube : Cube is a 3D shape which contains equal length, breadth and height. It have 8 vertex, 6 face and 12 edges.
e.g Cube and Dice etc.
Formula Related to Cube
Diagonal of cube = a√3 unit
T.S.A """"""""" = 6a² unit²
Volume """""""" = a³ unit³
[Where a is length of any equal side]
Cuboid : Cuboid is also a 3D shape which have similar properties like cube. But it's length breadth and height are not equal.
Formula Related to Cuboid.
Volume of Cuboid = l × b × h unit³
T.S.A of Cuboid= 2(lb+bh+lh) unit²
[Where l , b and h are length, breadth and height of any Cuboid]
Answer:
90 cm²
Explanation:
Given:
3 Cubes of volume 27 cm³ are joined end to end.
To find:
Total Surface Area (T.S.A)
Solution:
\because∵ Volume of cube = 27 cm³
\therefore \textsf{Side of cube} = \sqrt[3]{27} \:\:\:\:\textsf{cm}$^{3}$ \implies 3 \:\:\: \text{cm}
So the side of each cube is 3 cm.
\because∵ All the cubes are joined end to end. (See In Attachment)
\therefore∴ Length(l) of new cuboid = (3+3+3)
= 9 cm
Breadth(b) = 3 cm
Height(h) = 3 cm
So, T.S.A = 2(lb+bh+lh)
= 2{(9×3)+(3×3)+(3×3)}
= 2(27 + 9 + 9) cm²
= 2(45) cm²
= 90 cm²
Additional Information:
Cube : Cube is a 3D shape which contains equal length, breadth and height. It have 8 vertex, 6 face and 12 edges.
e.g Cube and Dice etc.
Formula Related to Cube
Diagonal of cube = a√3 unit
T.S.A """"""""" = 6a² unit²
Volume """""""" = a³ unit³
[Where a is length of any equal side]
Cuboid : Cuboid is also a 3D shape which have similar properties like cube. But it's length breadth and height are not equal.
Formula Related to Cuboid.
Volume of Cuboid = l × b × h unit³
T.S.A of Cuboid= 2(lb+bh+lh) unit²
\textsf{Diagonal of Cuboid} = \sqrt{l^2+b^2+h^2} \:\:\:\:\: \text{unit}Diagonal of Cuboid=
l
2
+b
2
+h
2
unit
[Where l , b and h are length, breadth and height of any Cuboid]