Question

3 cubes whose measures are 3 cm,4 cm,5 cm are joined to form a single cube . find its edge and surface area

Answer 1

The sum of the volume of the smaller cubes= volume of the larger cube
Let the side of the larger cube be'a'.
$3^{3} + 4^{3} + 5^{3}$=$a^{3}$
27+64+125=$a^{3}$
a=$\sqrt[3]{216}$
a=6cm
therefore side of the larger cube is 6cm
the surface area of the larger cube is 6$a^{2}$=6($6^{2}$)
=216$cm^{2}$