3.
Derive the equation of KE per mole, using the equation of pressure exerted by the gas on the walls of the
container
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1
Answer:
Kinetic energy of the gas K=
2
1
mv
rms
2
Rms velocity of gas molecules v
rms
=
m
3RT
∴ K=
2
1
m.
m
3RT
=
2
3
RT
From ideal gas equation, RT=PV
⟹ K=
2
3
PV
Thus we get pressure of the gas P=
3
2
V
K
Explanation:
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