Question

3 Derive the expression for the write
the relationship between for an
isochoric process.​

Answer 1

Answer:

Good morning dear have a great day

Answer 2

Explanation:

The work done by a system at constant temperature and pressure is given by

W = Pext ∆V _(1)

Assuming Pext=P

W= -P∆V

= -P (V2-V1)

= -PV2 + PV1 _(2)

If the gases were ideal at constant temperature and pressure,

PV1=n1RT and PV2=n2RT _(3)

Substitution of Eq(3) Eq(2)

W= -n2RT + n1RT

= - ( n2 - n1 ) RT

= - ∆ngRT _(4)

Eq (4) gives the work done by the system in chemical reactions.

Relationship between ∆H and ∆U for an isochoric process:

For an isochoric process, ∆V = 0

∆H = ∆U + P∆V

∆H = ∆U + P × 0

∆H = ∆ U + 0

Hence, ∆H = ∆U