3 Derive the expression for the write
the relationship between for an
isochoric process.
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Answer:
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Answered by
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Explanation:
The work done by a system at constant temperature and pressure is given by
W = Pext ∆V _(1)
Assuming Pext=P
W= -P∆V
= -P (V2-V1)
= -PV2 + PV1 _(2)
If the gases were ideal at constant temperature and pressure,
PV1=n1RT and PV2=n2RT _(3)
Substitution of Eq(3) Eq(2)
W= -n2RT + n1RT
= - ( n2 - n1 ) RT
= - ∆ngRT _(4)
Eq (4) gives the work done by the system in chemical reactions.
Relationship between ∆H and ∆U for an isochoric process:
For an isochoric process, ∆V = 0
∆H = ∆U + P∆V
∆H = ∆U + P × 0
∆H = ∆ U + 0
Hence, ∆H = ∆U
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