Question

3. Derive the expression for Time of flight, Horizontal rangeand
maximum height in angular projection of projectile.​

Answer 1

Answer:

Complete step by step answer:

Let a projectile be projected at an angle θwith the initial velocity u. ... As the value of the velocity is zero, substitute the same in the above equation. 0=usinθ−gt⇒t=usinθg. Hence the expression for the time of ascent.