Question

3. Determine if the points (1,5), (2, 3) and (-2,- 11) are collinear. ​

Answer 1

• A(1,5), B(2, 3)andC(-2,-11) Now, AB = √(1²) + (2²) = √5
• A(1,5), B(2, 3)andC(-2,-11) Now, AB = √(1²) + (2²) = √5BC = √(4²) + (14²) = √212
• A(1,5), B(2, 3)andC(-2,-11) Now, AB = √(1²) + (2²) = √5BC = √(4²) + (14²) = √212CA = √(1²) + (16²) = √257
• A(1,5), B(2, 3)andC(-2,-11) Now, AB = √(1²) + (2²) = √5BC = √(4²) + (14²) = √212CA = √(1²) + (16²) = √257As, CA > BC > AB
• A(1,5), B(2, 3)andC(-2,-11) Now, AB = √(1²) + (2²) = √5BC = √(4²) + (14²) = √212CA = √(1²) + (16²) = √257As, CA > BC > ABIf points A, BandC are collinear then
• A(1,5), B(2, 3)andC(-2,-11) Now, AB = √(1²) + (2²) = √5BC = √(4²) + (14²) = √212CA = √(1²) + (16²) = √257As, CA > BC > ABIf points A, BandC are collinear thenAB + BC = CA
• A(1,5), B(2, 3)andC(-2,-11) Now, AB = √(1²) + (2²) = √5BC = √(4²) + (14²) = √212CA = √(1²) + (16²) = √257As, CA > BC > ABIf points A, BandC are collinear thenAB + BC = CABut √5 + √212 + √257
• A(1,5), B(2, 3)andC(-2,-11) Now, AB = √(1²) + (2²) = √5BC = √(4²) + (14²) = √212CA = √(1²) + (16²) = √257As, CA > BC > ABIf points A, BandC are collinear thenAB + BC = CABut √5 + √212 + √257So they are not collinear.

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