Question

3. Determine the set of resolutions From the system of equations Y = -x2 + 4x-2 Y = -x + 2

Answer 1

Answer:

y = -x + 2

// substitute y //

y = -x² + 4x-2

-x + 2 = -x² + 4x-2

x²-x-4x + 2 + 2 = 0

x²-5x + 4 = 0

(x-1) (x-4) = 0

x-1 = 0

x = 1

x-4 = 0

x = 4

y = - (4) +2

y = -2

y = - (1) +2

y = 1

HP = {x, y}

HP = {1,1} or {4, -2}

So the values of x and y are 1 and 1 or 4 and -2, respectively

Answer 2

Answer:

Step-by-step explanation:

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