3) Diagonals of rhombus are 16cm and
12 cm. Find the side of the rhombus.
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Answer:
The answer is 10 cm
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Step-by-step explanation:
lets us take Rhombus as ABCD
diagonals are BC & AD
Let BC = 16cms
AD=12cms
so O will be the intersecting point of both diagonals BC& AD .
BC=12 CMS then BO +OC = 16 CMS ( 8cm+8cm) BO=OC
Similarly
AD=12cms then AO + OD =12cms ( 6cm+6cm) AO=OD
Using Pythagoras theorem
a^2+ b^2=c^2
so 8^2 + 6^2 = c^2
then 64 + 36 = 100
c^2 = 100
c=√100
c= 10cms
so the side of rhombus is 10 cm as. AB=BC =CD=AD
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