Question

3 different railway passes are allotted to 5 students. The number of ways this can be done is

Answer 1

Assuming one student can have only one pass:

First pass can be given to any of the 5 students.

Second pass can be given to any of the remaining 4 students

Third pass can be given to any of the remaining 3 students.

So, number of ways = 5 * 4* 3 = 60 ways.

Answer 2

There are 60 ways to do so.

Step-by-step explanation:

Since we have given that

Number of students = 5

Number of different railway = 3

We need to find the number of ways to do so.

Since there is an arrangement, so we will use "Permutation".

Here, n = 5

r = 3

So, it becomes,

$^nP_3=^5P_3=60$

Hence, there are 60 ways to do so.

# learn more:

In how many ways can 6 boys be allotted into 5 rooms such that no room is empty and all 6 boys are accommodated

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