Question

3-digit number 2a3 is added to
the numbes 326 to give a 3-dit be
number 5b9 which is divisible by 9 Find the
value of b-a​

Answer 1

Answer:

The sum of the digits of 5b9 must be divisible by 9

5+b+9=14+b.Hereb must be 4

2a3+326=549

=>2a3=549326

=223.

∴a=2 and b=4

Hence b-a= 4-2

=2