Question

3 digit number less than 200 divisible by 3 and 5​

Answer 1

Answer:

answer ha lele mera aur apne ma ko de dena

Answer 2

Step-by-step explanation:

Let A be the set of all numbers less than 250 and are divisible by 3. n(A) = (249–3)/3 + 1 =83

Let B be the set of all numbers less than 250 and are divisible by 5. n(B)=(245–5)/5 + 1=49

Let C be the set of all numbers less than 250 and are divisible by 11. n(C)=(242–11)/11 +1=22

AnB is the set of all numbers divisible by both 3 and 5. n(AnB) = no.of multiples of 15=240/15=16

BnC=set of numbers divisible by both 5 and 11

n(BnC)=220/55= 4

AnC=set of numbers divisible by both 3 and 11. n(AnC)=231/33 = 7

(AnBnC)=set of numbers divisible by 3,5 and 11 n(AnBnC )= 230/165 =2

So number of numbers divisible by 3 or 5 or 11 =n(AuBuC)=n(A)+n(B)+n(C)-n(AnB)-n(BnC) -n(AnC) + n(AnBnC) = 83+49+22–16–4–7+2=129