3. Divide the Polynomial 3x4+4x3-4x+3 by x-1.
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3
Answer:
Step-by-step explanation: let p(x)=3x^4+4x^3-4x+3
let g(x)=x-1
x-1=0
x=1
so in order to divide p(X) by g(x) we must put the value of x in p(x) and if after solving it there is some no. remaining we will count that as remainder
p(1)=3(1)^4+4(1)^3-4(1)+3
=3*1+4*1-4*1+3
=3+4-4+3
=3+3
=6
hence when we divide p(x)by g(x) remainder comes 6
Answered by
0
Answer:
this is the correct answer with remainder theorem
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