Math, asked by ruplalmandal68, 23 days ago

3. Do the following in your notebook.

a. A shopkeeper bought rice at the rate of Rs 20 per sack of rice. He bought 50 sacks of rice and sold them. He made a profit of Rs 400. At what rate did he sell the rice?

b. A textile shop owner purchased cloth at the rate of Rs 60 per metre. Unfortunately the business was dull and he had to sell the cloth at a loss of Rs 10 per metre. If he sold 100 metres, what is the total SP of the cloth?

C. Leena bought 2 saris for Rs 200 each and embroidery materials for Rs . 100. She embroidered both the saris identically. She sold one sari for a profit of Rs 100 and the other sari for a loss of Rs 50. What was the SP of each sari?​

Answers

Answered by Parshva123321
0

a.Cost Price of the rice=20×50=Rs.1000

Selling price=profit +cost price=400+1000=1400

b.cost of 1 metre=Rs.60

loss on 1 metre= Rs 10

Selling price of 1 metre=cost-loss=60-10=Rs.50

Selling price of 100 metres=50×100=5000

c.Sari 1

cost of sari=Rs.200

cost of embroidery=Rs.50

cost price=200+50=Rs.250

profit=Rs.100

Selling price=250+100=350

Sari 2

cost price of sari 2 will be same as sari 1 i.e.Rs.250

Loss=Rs.50

Selling price=250-50=200

Answered by johnathanfrancis791
1

Step-by-step explanation:

a. CP of rice per sack = ₹20

CP of 50 sacks of rice = ₹(20x50)

= ₹1000

Gain = ₹400

SP = CP of 50 sacks of rice + Gain

1000 + 400

₹ 1400

b. CP of cloth per meter = ₹60

Loss = ₹10

SP = 50 X 1000

₹50000

c. CP of 2 saris = ₹200

CP of 1 sari = ₹100

Gain on 1st sari = ₹100

Loss on 2nd sari = ₹50

SP of 1st sari = gain + CP

= ₹200

SP of 2nd sari = loss - CP

= ₹ 50

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