3. Draw a circle of radius 3.5 cm and construct a pair of tangents to it from a point 8cm from the centre of
circle. Measure the length of the tangents
4. The perimeter of a circle with centre 'o' is 24cm. the angle formed by an arc of a
circle at its centre is 30º find the length of arc AB
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ANSWER:
(1) It is given that line AB is tangent to the circle at A.
∴ ∠CAB = 90º (Tangent at any point of a circle is perpendicular to the radius throught the point of contact)
Thus, the measure of ∠CAB is 90º.
(2) Distance of point C from AB = 6 cm (Radius of the circle)
(3) ∆ABC is a right triangle.
CA = 6 cm and AB = 6 cm
Using Pythagoras theorem, we have
BC2=AB2+CA2⇒BC=62+62‾‾‾‾‾‾‾√ ⇒BC=62‾√ cm
Thus, d(B, C) = 62‾√
cm
(4) In right ∆ABC, AB = CA = 6 cm
∴ ∠ACB = ∠ABC (Equal sides have equal angles opposite to them)
Also, ∠ACB + ∠ABC = 90º (Using angle sum property of triangle)
∴ 2∠ABC = 90º
⇒ ∠ABC = 90°2
= 45º
Thus, the measure of ∠ABC is 45º.
(1) It is given that line AB is tangent to the circle at A.
∴ ∠CAB = 90º (Tangent at any point of a circle is perpendicular to the radius throught the point of contact)
Thus, the measure of ∠CAB is 90º.
(2) Distance of point C from AB = 6 cm (Radius of the circle)
(3) ∆ABC is a right triangle.
CA = 6 cm and AB = 6 cm
Using Pythagoras theorem, we have
BC2=AB2+CA2⇒BC=62+62‾‾‾‾‾‾‾√ ⇒BC=62‾√ cm
Thus, d(B, C) = 62‾√
cm
(4) In right ∆ABC, AB = CA = 6 cm
∴ ∠ACB = ∠ABC (Equal sides have equal angles opposite to them)
Also, ∠ACB + ∠ABC = 90º (Using angle sum property of triangle)
∴ 2∠ABC = 90º
⇒ ∠ABC = 90°2
= 45º
Thus, the measure of ∠ABC is 45º.
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