3. Draw a line I and take a point P on it. Through P, draw a line segment PQ perpendicular to I. Now draw a perpendicular to PQ at Q (use ruler and Compass).
Answers
Answer:
Therefore, PQ\perp IPQ⊥I and QR \perp PQQR⊥PQ
Step-by-step explanation:
Given,
Draw a line II and take a point PP on it.Through PP , draw a line where PQ\perp IPQ⊥I .Now draw a perpendicular to PQPQ at QQ .
Following steps:
Draw a line II
Take a point PP on line II
Take any measure and draw a curve with PP as a center which cuts line II at AA and BB
From point AA and CC cuts on the curve like CC and DD
Draw two curve from point CC and DD which cuts at point QQ
Join PP and QQ where PQ\perp IPQ⊥I
Similarly, by the same process draw a perpendicular line QRQR on PQPQ as shown in figure.
Now, PQ\perp IPQ⊥I and QR \perp PQQR⊥PQ
Step-by-step explanation:
hope u like it
mark me brainlist
Answer:
The cube has a side of 8 cm.
Step-by-step explanation:
The volume of the metal sheet and the cube will be the same.
The metal sheet has the measurements,
\begin{gathered}length=32 \ cm\\\\breadth =8\ cm\\\\thickness = 2\ cm\end{gathered}
length=32 cm
breadth=8 cm
thickness=2 cm
So the volume of the metal sheet is,
Volume = length\times breadth\times thickness = 32\times 8\times 2 = 512\ cm^3Volume=length×breadth×thickness=32×8×2=512 cm
3
Let aa be the side of the cube. So the volume is,
volume = a^3volume=a
3
Since the volume of the metal sheet and cube are the same, we can equate the volume. So
\begin{gathered}\implies a^3=512\\\\\implies a=\sqrt[3]{512}=8 \ cm\end{gathered}
⟹a
3
=512
⟹a=
3
512
=8 cm
Thus the cube has a side of 8 cm.