Question

3. Draw the graph of the equation 2x + 3y = 11. Find from the graph value of y when
x= 1​

Answer 1

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The value of y is 3, when the value of x = 1.

The given equation is,

$2x+3y=11$

It is linear equation so the graph of the equation is a straight line.

To draw the graph of the equation, we have to find at least two points which satisfies the equation.

Put x = 1

$2(1)+3y=11$

$3y=11-2$

$y=3$

Therefore the value of is 3, when x=1 and the line passing through the point (1,3).

Similarly, by putting x=4, we get y=1, and putting x=-2 we get y=5. So, the line passing through the point (4,1), (-2,5) and (1,3).

The graph of the equation is given below.

Answer 2

Answer:

To draw the graph of the equation, we have to find at least two points which satisfies the equation. Therefore the value of is 3, when x=1 and the line passing through the point (1,3). Similarly, by putting x=4, we get y=1, and putting x=-2 we get y=5. So, the line passing through the point (4,1), (-2,5) and (1,3).