Question

3. Draw the graph of the equation x +2y-3=0. From your graph, find the value of y when ) x=5 = 5 and make the table​

Answer 1

$\red{\large\underline{\sf{Solution-}}}$

Given equation of line is

$\rm :\longmapsto\:x + 2y - 3 = 0$

can be rewritten as

$\rm :\longmapsto\:x = 3 - 2y$

Substituting 'y = 0' in the given equation, we get

$\rm :\longmapsto\:x = 3 - 2(0)$

$\rm :\longmapsto\:x = 3 - 0$

$\bf\implies \:x = 3$

Substituting 'y = 1' in the given equation, we get

$\rm :\longmapsto\:x = 3 - 2(1)$

$\rm :\longmapsto\:x = 3 - 2$

$\bf\implies \:x = 1$

Substituting 'y = 2' in the given equation, we get

$\rm :\longmapsto\:x = 3 - 2(2)$

$\rm :\longmapsto\:x = 3 -4$

$\bf\implies \:x = - \: 1$

Hᴇɴᴄᴇ,

➢ Pair of points of the given equation are shown in the below table.

$\begin{gathered}\boxed{\begin{array}{c|c} \bf x & \bf y \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf 3 & \sf 0 \\ \\ \sf 1 & \sf 1 \\ \\ \sf - 1 & \sf 2 \end{array}} \\ \end{gathered}$

➢ Now draw a graph using the points.

➢ See the attachment graph.

From graph, we conclude that

$\begin{gathered}\boxed{\begin{array}{c|c} \bf x & \bf y \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf 5 & \sf - 1 \end{array}} \\ \end{gathered}$

Answer 2

Answer:

This Answer is Correct

Step-by-step explanation:

I hope it's helpful

All Answer is same