3. Draw the graph of the straight line given by
the equation 4x - 3y + 36 = 0
Calculate the area of the triangle formed
by the line drawn and the co-ordinate
axes.
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equation 4x−3y+36=0
on x-axis we get the point y=0 , x= - 9
and on y-axis we get the point x=0, y= 12
therefore area of the triangle formed
b=9 and h=12
A=1/2∗b∗h
A=1/2∗9∗12
A=54
Area =54 sq. units
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