Question

3.
E and Fare respectively the mid-points of equal sides AB and AC of ABC
(See figure) Then

(A) BF=AC
(B) BE = AF
(C) CE = AB
(D) BF=AC
plz give me answer fast
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Answer 1

Answer:

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Answer 2

$Given \: E \: and \: F \: are \: mid point \: of \: equal \: sides \: AB \: and \: AC \: of \: triangle \: ABC</p><p></p><p> \\ In ΔABF and  ΔACE</p><p></p><p> \\ AB=AC  (given )</p><p></p><p> \\ ∠A=∠A  (common angle )</p><p></p><p> \\ AF=AE (halves of equal sides)</p><p></p><p> \\ ∴ΔABF≅ΔACE (SAS rule)</p><p></p><p> \\ ∴BF=CF (CPCT)</p><p></p><p>$

Hope it helps.

Please ignore the "<p> <p\>" .Please