(3)
E E
P Р
А
(3Z - 42)°
B
(2z - 13)°
С
Q
DO
F
In the figure, AB || CD, then find the value of z.
Solution :
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ANSWER
∠GEF=180−∠CEF(∵∠GEF and ∠CEF are complementary angles)
∴∠GEF=30
o
and ∠GCD=∠GEF (from the figure, CD∣∣EF)
⇒∠GCD=30
o
Now, ∠BCD=∠BCG+∠GCD
⇒∠BCD=25
o
+30
o
=55
o
∠ABC=∠BCD(∵AB∣∣CD)
∠ABC=x=55
o
Therefore the value of x is 55.
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