Question

3
एक परिवार में 3 बच्चे हैं। इनमें कम से कम एक लड़का होने की प्रायिकता होगी
In a family of 3 children, the probability of having atleast one boy is :
(A)
(100
-100​

Answer 1

The probability of having atleast one boy is 100

Answer 2

The required probability is $\frac{7}{8}$ or 0.875.

Step-by-step explanation:

Consider the provided information.

Let B represent the boy and G represent girl.

If family has 3 children, then the number of possible ways or the sample space is: {BBB, BBG, BGG, BGB, GBB, GBG, GGB, GGG}

$Probability = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$

Total number of ways in which at least one is boy is 7 .

Total number of ways are 8.

Hence, the required probability is: $Probability = \frac{7}{8}=0.875$

#Learn more

Find the probablity​

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