3.
एककश
करतल ध्व
वति
५.
Answers
Given area of field = 3584m
2
length = 64 m
We know area - length × breadth = l×b
b=
64
3584
=56m
Now Perimeter of field = 2[l+b]
=2[64+56]
Perimeters of field = 2[120]= 240 m.
for 5 rounds perimeter = 240×5=1200m
Given speed of boy = 6 km/h = 6×
18
5
=
3
5
m/sec
then time taken to cover 1200 m distance =
5
1200
×3
Time = 240×3sec
or Time = ooye zini bheji kya
Given area of field = 3584m
2
length = 64 m
We know area - length × breadth = l×b
b=
64
3584
=56m
Now Perimeter of field = 2[l+b]
=2[64+56]
Perimeters of field = 2[120]= 240 m.
for 5 rounds perimeter = 240×5=1200m
Given speed of boy = 6 km/h = 6×
18
5
=
3
5
m/sec
then time taken to cover 1200 m distance =
5
1200
×3
Time = 240×3sec
or Time =
60
240×3
min=12min
∴ 12 min required to complete 5 rounds of field.hlo btao
SUCH btao mujhe Shak hai
Given area of field = 3584m
2
length = 64 m
We know area - length × breadth = l×b
b=
64
3584
=56m
Now Perimeter of field = 2[l+b]
=2[64+56]
Perimeters of field = 2[120]= 240 m.
for 5 rounds perimeter = 240×5=1200m
Given speed of boy = 6 km/h = 6×
18
5
=
3
5
m/sec
then time taken to cover 1200 m distance =
5
1200
×3
Time = 240×3sec
or Time =
60
240×3
min=12min
∴ 12 min required to complete 5 rounds of field.hlo btao
SUCH btao mujhe Shak hai
Given area of field = 3584m
2
length = 64 m
We know area - length × breadth = l×b
b=
64
3584
=56m
Now Perimeter of field = 2[l+b]
=2[64+56]
Perimeters of field = 2[120]= 240 m.
for 5 rounds perimeter = 240×5=1200m
Given speed of boy = 6 km/h = 6×
18
5
=
3
5
m/sec
then time taken to cover 1200 m distance =
5
1200
×3
Time = 240×3sec
or Time =
60
240×3
min=12min
∴ 12 min required to complete 5 rounds of field.
60
240×3
min=12min
∴ 12 min required to complete 5 rounds of field.
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